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Algorithms

FizzBuzz

seoca 2019. 2. 24. 06:09

 

 

 

FizzBuzz

Write a program that prints the numbers from 1 to 100 and for multiples of '3' print "Fizz" instead of the number and for the multiples of '5' print "Buzz".

 

 

 

 

Solution in Java (Converting int to String)

1
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5
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8
9
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11
public class Main{
    public static void main(String[] args) {
        for (int i = 1; i <= 100; i++) {
            String j = ""; //String should be declared in the 'for loop'
            if(i % 3 == 0){ j += "fizz";}
            if(i % 5 == 0){ j += "buzz";}
            if(j == ""){j = Integer.toString(i);} //convert int to String to print numbers as we only print String 'J'
            System.out.println(j);
        }
    }
 }

cs

 

 

 

Converting Integer to String 

1 .  if (s == "") { s += i; }

 

- Doesn't convert int to String. It works, but It's not about appending, we should 'convert' int to String 

 

 

2.  if (s == "") { s = Integer.toString(i); }

 

- Using Integer.toString() 

 

 

3. if (s == "") { s = String.valueOf(i); }

 

- Using String.valueOf() 

 

output

 
 
1
2
Fizz
4
Buzz
Fizz
7
8
Fizz
Buzz
11
Fizz
13
14
FizzBuzz
16
17
Fizz
19
Buzz
Fizz
22
23
Fizz
Buzz
26
Fizz
28
29
FizzBuzz
31
32
Fizz
34
Buzz
Fizz
37
38
Fizz
Buzz
41
Fizz
43
44
FizzBuzz
46
47
Fizz
49
Buzz
Fizz
52
53
Fizz
Buzz
56
Fizz
58
59
FizzBuzz
61
62
Fizz
64
Buzz
Fizz
67
68
Fizz
Buzz
71
Fizz
73
74
FizzBuzz
76
77
Fizz
79
Buzz
Fizz
82
83
Fizz
Buzz
86
Fizz
88
89
FizzBuzz
91
92
Fizz
94
Buzz
Fizz
97
98
Fizz
Buzz
cs

 

 

 

 

 

 

 

 

Solution in JavaScript

function fizzbuzz() {

    for (let i = 1; i < 101; i++) {
        if(i % 3 === 0){ console.log('Fizz');}
        if(i % 5 === 0){console.log('Buzz');}
        if(i % 15 === 0 ){ console.log('FizzBuzz');}

        console.log(i);
    }

}

fizzbuzz();

if else if 를 사용한다면 console.log 에서 꼭 else를 써야한다. 

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