Studying programming

Solution in Javascript const n = 3; function viralAdvertising(n) { let k = 5; let j = 0; let sum = 0; for(let i = 0; i < n; i++){ j = Math.floor(k/2); k = j * 3; sum+=j; } console.log(sum); } viralAdvertising(n); *Use Math.floor() to get quotient. Reference www.hackerrank.com/challenges/strange-advertising/problem

Solution in Javascript I const k = 3; const a = [-1, -3, 4, 2]; function angryProfessor(k, a) { const p = a.filter(v => v < 1).length < k ? 'YES' : 'NO' return p; } angryProfessor(k, a); 1. To filter elements which are less than 1, use filter() 2. length() is used to get the number of the elements. for loop 와 if 를 사용하는 것보다 내장 함수들을 사용하자. Solution in Javascript II const k = 4; const a = [-1, -3, -..